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Time signatures and beat calculations
Right, I have some gaps in my musical knowledge and I am hoping someone can fill them for me...
With time signatures I know that 4/4 means there are 4 instances of a 1/4 note per measure. So 5/8 would mean that there are 5 instances of an 1/8 note per measure. My question is this - does that mean that with a 5/8 time signature there are 5 beats per measure? So with a tempo of 100bpm and a time signature of 5/8, is the following maths correct: 300ms per 1/8 note (ie beat) and 1.5s per measure I think I have but would appreciate someone confirming this or if not then explaining it in simpleton terms. Thanks, Drammy |
Re: Time signatures and beat calculations
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Thanks Juho...
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Sorry to bring this post back up again, but I still can't get my head around something. Problem is I am not too sure what it is I cannot get my head around...
Lets take a track with a tempo of 120bpm. If the signature is 4/4 then each beat lasts for 500 ms... (correct?) Now what...? How long would each beat last for if the signature is 6/8? Sorry to be a school teacher but you must show your workings... Ta, Drammy |
Im gonna take a wild guess and say that nothing has changed...
Only now, you have 6 8th notes per bar (cant remember technical term), but your tempo is still 120BPM, so each beat still is only 0.5s Am I right??? EDIT: Geez... I was so wrong!!!! Maths was never my strong point, so why am I studying acoustics at uni? Crazy I tells ya.... |
I don't know, thats the problem.
Or has the fact that the 4th has become an eigth - made the length of the beat half? It is all so confusilating (I've been playing Ratchet and Clank 2). |
just use timings based on the smallest reasonable measure
125ms so, 125ms, 250ms, 500ms, 375ms(250ms+125ms) get tricky, 62.5ms+125ms=187.5 187.5ms+250ms=437.5ms try em, mix em right channel 250ms, left channel 375ms, feedback 187.5ms etc etc etc There is a simple formula for BMP to Milliseconds, do a Google. |
Divide 60000 by your tempo to find the ms of a 1/4 note.
IE: 60000/132 = 1/4 note that's 454.54ms long To find an 1/8th note, just halve the answer, IE 227.27ms |
Yeah I get all this guys,
Thing is I am writing a delay calc for myself in Visual Studio and I am trying to work out how to calculate delays on different time signatures... I have all the 1/1, 1/2, 1/4, 1/8 and so on notes worked out for normal notes, dotted notes and triplets, but I don't quite understnad the effect of a time signature on a beats length. Although my investigations are leading me to believe that it doesn't matter... Anyone for input? |
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